4[c+12]=2c+18

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Solution for 4[c+12]=2c+18 equation:


Simplifying
4[c + 12] = 2c + 18

Reorder the terms:
4[12 + c] = 2c + 18
[12 * 4 + c * 4] = 2c + 18
[48 + 4c] = 2c + 18

Reorder the terms:
48 + 4c = 18 + 2c

Solving
48 + 4c = 18 + 2c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-2c' to each side of the equation.
48 + 4c + -2c = 18 + 2c + -2c

Combine like terms: 4c + -2c = 2c
48 + 2c = 18 + 2c + -2c

Combine like terms: 2c + -2c = 0
48 + 2c = 18 + 0
48 + 2c = 18

Add '-48' to each side of the equation.
48 + -48 + 2c = 18 + -48

Combine like terms: 48 + -48 = 0
0 + 2c = 18 + -48
2c = 18 + -48

Combine like terms: 18 + -48 = -30
2c = -30

Divide each side by '2'.
c = -15

Simplifying
c = -15

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